Solve 23rd sum,h having doubt
Dear Student,
Please find below the solution to the asked query:
Given : AB = AC , From base angle theorem we get
ABC = ACB = x --- ( 1 )
And we know from external angle theorem :
CAD = ABC + ACB , Substitute values from equation 1 we get
CAD = x + x ,
CAD = 2 x , Also given AE is bisector of CAD , So
DAE = CAE = x --- ( 2 )
From equation 1 and 2 we get
DAE = ABC and these are corresponding angles , we take BD as transversal line and that can only be true if
BC | | AE ( Hence proved )
Regards
Please find below the solution to the asked query:
Given : AB = AC , From base angle theorem we get
ABC = ACB = x --- ( 1 )
And we know from external angle theorem :
CAD = ABC + ACB , Substitute values from equation 1 we get
CAD = x + x ,
CAD = 2 x , Also given AE is bisector of CAD , So
DAE = CAE = x --- ( 2 )
From equation 1 and 2 we get
DAE = ABC and these are corresponding angles , we take BD as transversal line and that can only be true if
BC | | AE ( Hence proved )
Regards