Dear student, 30 oxen can plough 1/7 th of a field in 2 days 1 oxen can plough 1/7 th of a field in 2×30 days 18 oxen take to do 1/7 th work in 2×3018 daysBut the remaining work =1-17=67 18 oxen take to do 6/7th work = 6×2×3018 days=6×1×309=2×303=2×10=20days Regards

Solve 4th question

Dear student,

30 o x e n c a n p l o u g h 1 / 7 t h o f a f i e l d i n 2 d a y s 1 o x e n c a n p l o u g h 1 / 7 t h o f a f i e l d i n 2 \times 30 d a y s 18 o x e n t a k e t o d o 1 / 7 t h w o r k i n \frac{2 \times 30}{18} d a y s B u t t h e r e m a i n i n g w o r k = 1 - \frac{1}{7} = \frac{6}{7} 18 o x e n t a k e t o d o 6 / 7 t h w o r k = \frac{6 \times 2 \times 30}{18} d a y s = \frac{6 \times 1 \times 30}{9} = \frac{2 \times 30}{3} = 2 \times 10 = 20 d a y s

Regards

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