solve by substitution method:-

2x-y=3

4x-y=5

the given set of linear equations are:

from eq(1):

substituting the value of y from eq(1) in eq(2):

put x = 1 in eq(1):

thus x = 1 and y = -1 is the solution of the given equation.

hope this helps you.

cheers!!

  • 0

 2x-y=3

2x=3+y

x=3+y/2

now substitute this value in equation two

4(3+y/2)-y=5

2(3+y)-y=5

6+2y-y=5

y=-1

now substitute this value in equation 1

2x-(-1)=3

2x=3-1

x=1

  • -2
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