solve for x and y . 2/(3x+2y)+3/(3x-2y)=17/5 5/(3x+2y)+1/(3x-2y)=2 Share with your friends Share 7 Manbar Singh answered this Let 13x + 2y =p and 13x - 2y = qthen the given equations become:2p + 3q = 175 ...........15p + q = 2 ............2Multiplying equation 1 by 5 and equation 2 by 2, we get,10p + 15q = 17 ............310p + 2q = 4 ...........4Subtracting equation 4 from equation 3, we get, 13q = 13⇒ q = 1313⇒ q = 1Putting q = 1 in equation 3, we get, 10p + 15 × 1 = 17⇒ 10p + 15 = 17⇒ 10p = 17 - 15⇒ 10p = 2⇒ p = 210⇒ p = 15 Therefore, 13x + 2y = 15 and 13x - 2y = 1⇒ 3x + 2y = 5 .........5 and 3x - 2y = 1 ..........6Adding equation 5 and equation 6, we get, 6x = 6⇒ x = 66⇒ x = 1Putting x = 1 in equation 5, we get, 3 × 1 + 2y = 5⇒ 3 + 2y = 5⇒ 2y = 5 - 3⇒ 2y = 2⇒ y = 22 = 1Hence, the solution is x = 1 and y = 1 8 View Full Answer
