Solve for x ax2 + (4a2 - 3b)x - 12ab = 0 - Maths - Quadratic Equations

Question

Solve for x ax2 + (4a2 - 3b)x - 12ab =
0

Vaibhav Thakur · Answer

here a=a, b=(4a2-3b) ,and
c=-12ab

by quadratic equation we get,
<img src=
"http://upload%20wikimedia%20org/math/3/e/a/3ea647783b5121989cd87ca3bb558916%20png"
alt="x=frac{-b pm sqrt {b^2-4ac}}{2a},">
= -(4a2-3b) _+ root (4a2-3b)2 - 4 (a)(-12ab)/2(a)
=-(4a2-3b) _+ root (4a2 )2+(3b)2 - 2(4a2)(3b) +48a2b/2a
=-(4a2-3b)_+root (4a2)2 + (3b)2 -24a2b + 48a2b/2a
=-(4a2-3b)_+root (4a2)2 +(3b)2 + 24a2b/2a
=-(4a2-3b) _+ root (4a2 + 3b)2/2a
=-(4a2-3b)_+(4a2 + 3b)/2a
so, x= -(4a2-3b) + (4a2+3b)/2a or x = -(4a2-3b) -
(4a2+3b)/2a
x = 6b/2a or x = -8a2/2a = -4a
hope it helps

Solve for x. ax2 + (4a2 - 3b)x - 12ab = 0

Solve for x. ax²+ (4a² - 3b)x - 12ab = 0