Solve it please urgent

Solve it please urgent . Atransversal cuts tun parallel lines atAarul The Iwo nrteriar angles at A and So are the two interior angles at B; the four bisectors form a quadrilateral Prove that (i) ACBDisareetangIcm CD is parallel to the original prallel lines,

Hi,

for line l, angle PAB + angle BAS = 180, linear pair multiply by half, both side \frac{1}{2} anglePAB + \frac{1}{2} angle BAS = 90 angle BAC + angle BAD = 90 angle CAD = 90 SO, ACBD is a parallelogram in which one angle is 90 Hence ACBD is a rectangle

h e r e a n g l e Q B C = a n g l e C B T \{B C i s b i s e c t o r o f a n g l e Q B T\} a n d T C = T B s o a n g l e T B C = a n g l e T C B c o m b i n i n g t h e s e t w o r e s u l t s a n g l e Q B C = a n g l e T C B s o t h e s e a r e a l t e r n a t e i n t e r i o r a n g l e a n d B C i s t r a n s v e r s a l s o C T ∥ m o r C D ∥ m a n d h e n c e C D ∥ l