solve NO SIMILAR QUE
Q.1. Calculate the work done when a spherical drop of mercury of radius 2 mm, falls from some height and breaks into a million droplets, each of the same size. The surface tension of mercury is T = 0.5 N/m.

Dear student,


Work done= T.dswhere ds is the change in area.Volume of the large drop= 43πR3Volume of the small drop= 43πr3so 43πR3=n43πr3or R3=106r3or  r=R100Change in surface areads=4π(nr2-R2)    = 4π(106×R2104-R2)      =99×4×π×R2=4973×10-6m2work done = T.dsW=0.5×4973×10-6m2W=0.248×10-2J

 
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