solve Q 18 ans. 1.5ml plz dont give link

solve Q 18 ans. 1.5ml plz dont give link .16 Q.17 QIR Q.19 Q.20 Q.21 Q.22 0.23 Determine the volume (in mC) otdilLlted nitric acid 1.11 g mL l, w/v H.X();) thntcanbc prepared by diluting 50 mL ofcone_ IINO/ with water (d 21.42 g mL l, 69.8% w 500 ml of2 MNaCl solution was mixed with 200 ml ol'2 M NaCl solution. Calculate (he final and tmlarity ofNaCl in linal solution if final solution his density .5 gm'ml. Calculate the amount watcr "in m f"which must he added to a given solution Ofconcentration Of 40 mg silver nitrate per to yield a solution Of concentration Of 16 mg silver nitrate per ml ? A mixture containing equimolar amounts Of Ca(OH). and AI(OH), requires O.S L of 4.0 VI I to react With it completely. Total moles Of the mixture are 500 gm or urea solution of mole fraction 0.2 is diluted to I SOO gm. Calculate the fraction Of solute in the diluted solution ? When V ml of2,2 M VliS04 solution is mixed with I O V rill ofwatcr, the volume contraction Of2% take place. Calculate the molarity diluted solution What volume (in mC) of 0.8 M AICII solution should be mixed with 50 of0.2M CaCl, solutio .4 to get solution ofchloride ion concentration equal to 0.6 M ? An oleum sample iOahclled as 1 18 Calculate Mass or H2S04 in 100 gm oleum sample.

Molar molecular mass of silver nitrate =169.9 g/mol

Number of moles in 16 mg or silver nitrate = 16 x 10^-3g / 169.9 gmol^-1

= 9.417 x 10^-5 mol

Number of moles in 40 mg of silver nitrate = 40 x 10^-3 g / 169 gmol^-1

= 23.67 x 10^-5 mol

Molarity of 1^st solution (M₁) = 9.417 x 10^-5 mol/ml

Molarity of 2^nd solution (M₂) = 23.67 x 10^-5 mol/ml

Let V ml of water is added to 1^st solution of M₁molarity to change to change it into 2^nd solution of M₂ molarity.

i.e...

(9.417 x 10^-5 mol) / (1 ml) = (23.67 x 10^-5 mol) / (1 ml+ V ml)

By solving the above equation

V = 1.5135 ml