solve Q 7 (plz dont give link) ans. 0.15M
Let,.average concentration is 4 g per liter. Now, for 1 L solution, mass of solute (Na+ion)= 4 g
So, no. of moles of Na+ion = given mass/ molar mass = 4/23 =0.17 g
Hence, molarity = moles/Volume in L= 0.17/1= 0.17M
So, no. of moles of Na+ion = given mass/ molar mass = 4/23 =0.17 g
Hence, molarity = moles/Volume in L= 0.17/1= 0.17M