Solve:

Q. If a = 21/3 – 2–1/3, then show that 2a3 + 6a – 3 = 0:

Hi, a = 213- 2-13taking cube a3= 213- 2-133=2133- 2-133-3×213× 2-13 213- 2-13a3=2-12-3×213-13×a  putting back a = 213- 2-13 a3=32-3a2a3+6a-3=0

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