Solve question 3 1st and 2 nd sum
Dear student,
We know, if a number is divisible by 9 then it must be divisible by 3 and a number is divisible by 3 if the sum of its digits is divisible by 3.
(i) 45639
sum of digits=4+5+6+3+9=27, which is divisible by 3.
So, 45639 is divisible by 3.
(ii) 301248
sum of digits= 3+0+1+2+4+8=18, which is divisible by 3.
so, 301248 id divisible by 3.
Regards!
We know, if a number is divisible by 9 then it must be divisible by 3 and a number is divisible by 3 if the sum of its digits is divisible by 3.
(i) 45639
sum of digits=4+5+6+3+9=27, which is divisible by 3.
So, 45639 is divisible by 3.
(ii) 301248
sum of digits= 3+0+1+2+4+8=18, which is divisible by 3.
so, 301248 id divisible by 3.
Regards!