solve quo ii 11/3 karke

\frac{3}{x + y} + \frac{2}{x - y} = 3 \frac{2}{x + y} + \frac{3}{x - y} = \frac{11}{3} Let \frac{1}{x + y} = u and \frac{1}{x - y} = v So, the equations becomes 3 u + 2 v = 3 . . . (i) 2 u + 3 v = \frac{11}{3} . . . (ii) Equation (i) \Rightarrow u = \frac{3 - 2 v}{3} Putting in (ii), we get 2 (\frac{3 - 2 v}{3}) + 3 v = \frac{11}{3} \Rightarrow \frac{6 - 4 v}{3} + 3 v = \frac{11}{3} \Rightarrow \frac{6 - 4 v + 9 v}{3} = \frac{11}{3} \Rightarrow 6 + 5 v = 11 \Rightarrow 5 v = 5 \Rightarrow v = 1 So, u = \frac{3 - 2 (1)}{3} = \frac{1}{3} So, \frac{1}{x + y} = \frac{1}{3} and \frac{1}{x - y} = 1 \Rightarrow x + y = 3 and x - y = 1 Adding the equations we get 2 x = 4 x = 2 and y = 1

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