Dear Student, We have N=N0e-λt=N0e- 693t1/2×1 44×t1/2=N0e- 997=N0e-1=N0e= 37N0So in mean time there will be 37% remaining of original Regards

Solve qus no. 27

Dear Student,

W e h a v e N = N_{0} e^{- λ t} = N_{0} e^{- \frac{. 693}{t_{1 / 2}} \times 1.44 \times t_{1 / 2}} = N_{0} e^{- . 997} = N_{0} e^{- 1} = \frac{N_{0}}{e} = . 37 N_{0} S o i n m e a n t i m e t h e r e w i l l b e 37 % r e m a i n i n g o f o r i g i n a l .

Regards