Solve root under 5 x square + x + root 5 Q.21. Solve 5 x 2 + x + 5 = 0 . Share with your friends Share 3 Akshita Goyal answered this Dear Student, 5 x2+x+5=0We know that the roots of the equation ax2+bx+c=0 is given by D= -b±b2-4ac2a⇒From given equation, a=5, b=1 and c=5⇒D=-1±12-4*5*52*5⇒D=-1±1-4*525⇒D=-1±-1925⇒D=-125±195i, where i is an imagionary number as i2=-1 Regards 1 View Full Answer Shivam answered this Please find this answer 3 Sakshi answered this a=root 5, b = 1, c =root 5 x = b +-Root(b2-4ac)/2a by substituting the values x = 1+-19i/2root5 0 Aashutosh Gaurav answered this Thanks for the answers guys. Really appreciate it 1 Singh answered this X^2 +x/2+1=0 -3 Singh answered this x^2+x/2+1=0 0 Singh answered this X^2 +x/2+1=0 -1 Sobhini Kurian answered this Maybe this helps you -1
