Solve sec^2A + tan^2A = 5/3

Dear Student,

$\Rightarrow$sec²A + tan²A = $\frac{5}{3}$
$\Rightarrow$1+ tan²A + tan²A = $\frac{5}{3}$         (Using sec²A - tan²A = 1 )
$\Rightarrow$1 + 2tan²A = $\frac{5}{3}$
$\Rightarrow$2tan^​2A = $\frac{5}{3}$ - 1
$\Rightarrow$2 tan²A = $\frac{2}{3}$
$\Rightarrow$tan²A = $\frac{1}{3}$
$\Rightarrow$tanA = $\pm \frac{1}{\sqrt{3}}$
$\Rightarrow$A = $\pm$ 30 degrees

Regards