solve the following quadratic equation: x2 - [ 3( root 2 ) - 2 i ] x - ( root - Maths - Linear Inequalities

Question

solve the following quadratic equation: x2 - [ 3( root 2
) - 2 i ] x - ( root 2 )i = 0

Rishabh Mittal · Accepted Answer

Dear Student ,

Please find below the solution to the asked query :

x2-32-2ix-2i=0a=1 , b=-32-2i and c=-2iD=b2-4ac=-32-2i2-41-2i=18+4i2-122i+42i=18-4-82i                             Since i2=-1=14-82iSo,x=-b±D2a=32-2i±14-82i2Now,
<img src=
"https://s3mn%20mnimgs%20com/img/shared/content_ck_images/ana_qa_image_57b2f155c8726%20png">

So,x=32-2i±4-2i2x=32-2i+4-2i2   or  x=32-2i-4-2i2x=32+4-i 2+22   or x=32-4-i 2-22   ANS
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solve the following quadratic equation: x2 - [ 3( root 2 ) - 2 i ] x - ( root 2 )i = 0

solve the following quadratic equation: x² - [ 3( root 2 ) - 2 i ] x - ( root 2 )i = 0