solve the following system of equation :
15x +23y = 50
23x + 15y= 26
Condition 1 :-
Add both eqn :-
38x + 38y = 76
= x + y = 2 ----------- 1 )
Condition 2 :-
Subtract both eqns :-
- 8x + 8y = 24
= x - y = - 3 --------- 2 )
Eliminating eqn 1 and 2 we get :-
2y = 5
y = 5 / 2 ------- 3 )
Substituting 3 ) in eqn 2 ) we get :-
x - 5 / 2 = - 3
x = - 1 / 2 ----------- 4 )
Hope it helps ..!!!
Add both eqn :-
38x + 38y = 76
= x + y = 2 ----------- 1 )
Condition 2 :-
Subtract both eqns :-
- 8x + 8y = 24
= x - y = - 3 --------- 2 )
Eliminating eqn 1 and 2 we get :-
2y = 5
y = 5 / 2 ------- 3 )
Substituting 3 ) in eqn 2 ) we get :-
x - 5 / 2 = - 3
x = - 1 / 2 ----------- 4 )
Hope it helps ..!!!