Solve the17 one please

Dear Student,
in triangle DBE,
sum of all angles of a triangle = 180
Angle DBE + Angle BED + Angle EDB = 180
90 + 72 + Angle EDB = 180
162 + Angle EDB = 180
Angle EDB = 180 - 162 = 18

Sum of linear angles = 180
Angle BED + Angle CED = 180
72 + Angle CED = 180
Angle CED = 180 - 72 = 108

In triangle DEC,
Angle EDC + Angle DEC + Angle DCE = 180
Angle EDC + 108 + 52 = 180
Angle EDC = 180 - 160 = 20

Angle AFD = 52 
In triangle ADF,
Angle ADF + Angle DFA + Angle FAD = 180
Angle ADF + 52 + 56= 180
(Angle ADG + 18 + 20) + 108 = 180
Angle ADG = 180 - 108 - 38 
Angle ADG = 180 - 146 = 34

Angle ADG - Angle MDF = 34 - 20 = 14

Regards,