Solve this: 1 One mole of N2O4 (g) in a 1 L flask decornposes to attain the equilibrium - Chemistry -

Question

Solve this:

1 One mole of N2O4 (g) in a 1 L flask
decornposes to attain the equilibrium N2O4
(g) ⇌ 2NO2(g)
At the equilibrium the mole fraction of NO2 is 1/2 Hence
Kc will be:
(1) 1/3 (2) 1/2 (3) 2/3 (4) 1

Geetha · Accepted Answer

N2O4↔2NO2Initial:             1              -At eqm           1-x        2xTotal moles at eqm = 1-x+2x= 1+x  Mole fraction of NO2 = Number of moles of NO2Total moles = 2x1+xSo 2x1+x = 124x=1+x3x=1x=1/3 = 0
333At eqm          N2O4= 1-x = 1-0
33=0 67   [N2O4]=nv= 0 671=0
67    NO2=2x =2 (0 33)=0
66[NO2]=nv= 0 661=0 66Kc=[NO2]2[N2O4] =0 6620 67 =0
66 =23Thus option 3 is correct

Solve this: 1. One mole of N2O4 (g) in a 1 L flask decornposes to attain the equilibrium N2O4 (g) ⇌ 2NO2(g) At the equilibrium the mole fraction of NO2 is 1/2 Hence Kc will be: (1) 1/3 (2) 1/2 (3) 2/3 (4) 1

Solve this:

1. One mole of N₂O₄ (g) in a 1 L flask decornposes to attain the equilibrium N₂O₄ (g) $⇌$ 2NO₂(g)
At the equilibrium the mole fraction of NO₂ is 1/2 Hence K_c will be:
(1) 1/3 (2) 1/2 (3) 2/3 (4) 1