Solve this:

10.PQRS is a rectangle,A and B are points on side PQ and SR respectively such that BQ=AR. Show that AQ=BR and   ∠BQR=∠ARQ.(see figure 10)

angle AQR=angle BRQ (90 degrees), AR=BQ,QR ia common side so triangle BRQ is congruent to triangle ARQ by RHS test.AQ=BR and angle ARQ = angle BRQ because corresponding parts of congruent traingles are equal. 
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