Solve this: 108 The coordinate of the centre of the smallest circle passing through the origin - Maths - Linear Programming

Question

Solve this:

108 The coordinate of the centre of the smallest circle passing
through the origin & having y=x+1 as a diameter are-

1   1 2 , - 1 2 2   1 2 , 1 3 3   - 1 , 0 4   -
1 2 , 1 2

Aakash Sharma · Accepted Answer

The line y = x + 1 can be represented graphically as

So, the smallest circle having y = x + 1 as diameter and passing through origin will have centre at mid point of (-1, 0) and (0, 1) $\Rightarrow Required coordinates of centre of circle = (\frac{- 1 + 0}{2}, \frac{0 + 1}{2}) = (\frac{- 1}{2}, \frac{1}{2}) or (- 0 5, 0 5)$

Solve this: 108. The coordinate of the centre of the smallest circle passing through the origin & having y=x+1 as a diameter are- 1 1 2 , - 1 2 2 1 2 , 1 3 3 - 1 , 0 4 - 1 2 , 1 2

Solve this:

108. The coordinate of the centre of the smallest circle passing through the origin & having y=x+1 as a diameter are-

$(1) (\frac{1}{2}, - \frac{1}{2}) (2) (\frac{1}{2}, \frac{1}{3}) (3) (- 1, 0) (4) (- \frac{1}{2}, \frac{1}{2})$