Solve this:
A solution contains Na2CO3 and NaHCO3, 10 ml of the solution required 2.5 ml of 0.1 M H2SO4 for neutralization using phenolphthalein as indicator. Methyl orange is then added a further 2.5 ml of 0.2 M H2SO4 was mixed. The amount of NaHCO3 in one litre of the solution is
Na2CO3 = 5.3 g

Dear Student,

With phenolpthalene, the reaction occurring isNa2CO3 + H+  NaHCO3 + Na+To neutralise whole of Na2CO3, volume of H2SO4 will be twice of the given volumeN1 = (2×2.5)(2×0.1)10=0.1 NMass of Na2CO3 in 1L solution is =0.1×53=5.3 gVolume of sulphuric acid solution used in neutralising NaHCO3==2.5 mlHence, normality of NaHCO3 solution, N2=2.5×(2×0.2)10=0.1 NMass of NaHCO3 = 0.1×84=8.4 g 

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