Solve this mathematical question E s t a a b l i s h t h e i n e q u a l i t y n n ≥ 1 . 3 . 5 . . . . . ( 2 n - 1 ) , n ∈ N U n d e r w h a t c o n d r f t h e e q u a l i t y h o l d s Share with your friends Share 0 Zuhaib Ul Zamann answered this Dear student, RHS=1*3*5*...*2n-1=1×2×3×....×2n-1×2n2×4×6...×2n=2n!2nn!So overall inequality becomes2nn≥2n!n!2nn≥2n2n-1...n+1 Now we know that 2n≥2n2n≥2n-12n≥2n-2⋮ ⋮2n≥n+1So we have 2n2n-n+1+1≥2n2n-1...n+1 ⇒2nn≥2n2n-1...n+1 Hence the given inequality holds for all nRegards 0 View Full Answer