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E s t a a b l i s h   t h e   i n   e q u a l i t y   n n 1 . 3 . 5 . . . . . ( 2 n - 1 ) , n N U n d e r   w h a t   c o n   d r f   t h e   e q u a l i t y   h o l d s

Dear student,
RHS=1*3*5*...*2n-1=1×2×3×....×2n-1×2n2×4×6...×2n=2n!2nn!So overall inequality becomes2nn2n!n!2nn2n2n-1...n+1 Now we know that 2n2n2n2n-12n2n-2          2nn+1So we have 2n2n-n+1+12n2n-1...n+1 2nn2n2n-1...n+1 Hence the given inequality holds for all nRegards

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