Solve this:- No links plz Q) Prove that: sinθ+secθ2+cosθ+cosecθ2=1+secθ cosecθ - Maths - Introduction to Trigonometry

Question

Solve this:- No links plz
Q) Prove that: sin θ + s e c θ 2 + cos θ + cos e c
θ 2 = 1 + s e c θ cos e c θ

Varun Rawat · Accepted Answer

LHS = sin θ + sec θ2 + cos θ + cosec θ2= sin θ + 1cosθ2 + cos θ + 1sin θ2=sin2θ + 1cos2θ + 2 ×sin θcos θ + cos2θ + 1sin2θ  + 2 × cos θsin θ=sin2θ  +  cos2θ + 1cos2θ + 1sin2θ  + 2sin θcos θ + cos θsin θ=1 + sin2θ  +  cos2θcos2θ 
 sin2θ + 2sin2θ  +  cos2θsin θ 
 cos θ=1 + 1cos2θ 
 sin2θ + 2 × 1sin θ 
 cos θ=1 + sec2θ 
 cosec2θ + 2 sec θ 
 cosec θ=1 + sec θ 
 cosec θ2=RHS

Solve this:- .... No links plz Q). Prove that: sin θ + s e c θ 2 + cos θ + cos e c θ 2 = 1 + s e c θ . cos e c θ

Solve this:- .... No links plz
Q). Prove that: ${[\sin θ + s e c θ]}^{2} + {[\cos θ + \cos e c θ]}^{2} = 1 + s e c θ . \cos e c θ$