Solve this:
Q. (iii) a - 1 + b - 1 ÷ a b - 1 + a - 1 - b - 1 ÷ a - 2 - b - 2

Hi, a-1+b-1ab-1+a-1-b-1a-2-b-2=1a+1b1ab+1a-1b1a2-1b2=a+bab1ab+b-aabb2-a2a2b2=a+bab×ab1+b-aab×a2b2b2-a2=a+b+b-a1×abb-ab+a=a+b+abb+a=b+a2+abb+a=a2+b2+3aba+b

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