Solve this: Q18. A radioactive element 90X238 decays into 83Y222, then the number of β - particles emitted are (1) 1 (2) 2 (3) 4 (4) 6 Share with your friends Share 12 Deepak Kumar answered this Dear Student X23890→Y22283now we have to find number of β-particle 1) no of α-particle = 238-2224 =164 =42) no ofβ-particle = 83 - (90-4*2) = 83-82 = 1 So option no. (1) is correct Regards 11 View Full Answer Nayan answered this I think the solution in the picture will be enough sweety 11
