Solve this:
Q19. A point charge q moves from point P to point S along the path PQRS (figure ) in a uniform electric field E pointing parallel to the positive direction of the X - axis. The co-ordinates of the points P,Q,R and S are (a , b, 0 ). (2a, 0 , 0) , (a, – b, 0) and (0 , 0 ,0) respectively. The work done by the field in the above process is :-
(1) qEa (2) – qEa
(3) qEa (4) qE
Dear Student,
as electric field is along the x-axis so work done=qE(2a-a)+qE(a-2a)+qE(0-a)=-qaE
Regard