Solve this: y = sin² 3 . tan³ 2x .

Dear student
Assuming the question is to differentiate.
$$\begin{gathered} y={\sin }^{2}3.{\tan }^{3}2x \\ Differentiate w.r.t x we get \\ \frac{dy}{dx}={\sin }^{2}3\left(3{\tan }^{2}2x\right)\left(se{c}^{2}2x\right)2 \\ =6{\sin }^{2}3{\tan }^{2}2xse{c}^{2}2x \end{gathered}$$
Regards