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Please find below the solution to the asked query :

In Quadrilateral PQRS ,∠P+∠Q+∠R+∠S=360°100°+∠Q+110°+75°=360°285°+∠Q=360°∠Q=75°Steps of construction:1 Draw a line segment PQ=3.8 cm2 At point Q , Draw an angle PQX=75°3 Taking Q as centre , Draw an arc of length 6.8 cm which cuts QX at R.4 At point R , draw an angle of 110° and at point P , draw an angle of 100°. Which meets at point S.PQRS is a required quadrilateral .

 
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its simple go step by step construction
 
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angle P + angle Q + angle R+angle S = 360 degree

therefore angle Q= 75 degree
after this hint i think uh can solve it further  .....do like .
 
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