Solve this:

Solve this: 140. Oxidation number of iron in

Dear Student,

The charge on the coordination sphere will be - 2 {Na}_{2} [Fe (CN)_{5} (NO)] = {Na}^{+} [Fe (CN)_{5} (NO)]^{2 -} So, oxidation number of Fe in [Fe (CN)_{5} (NO)]^{2 -} can be calculated as : (oxidation number of Fe) + 5 (oxidation number of CN) + (oxidation number of NO) = Charge on coordination sphere or, oxidation number of Fe + 5 (- 1) + 1 = - 2 or, oxidation number of Fe = - 2 + 4 or, oxidation number of Fe = + 2 Hence, oxidation number of iron is + 2 Therefore, correct answer is (1)