Dear student Fraction of children=410=25Fraction of ladies=310Fraction of men=1-25+310=310Difference between the fraction of men and children=25-310=110Now, it is given that this 110 is equal to 28So, Total number of people in the audience was 28×10=280

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Solve this 45 kgs d. 25 kgs 79. At a seminar — of the audience were children, — were ladies. The rest were men. If the 10 10 number of children was 28 more than men, then the total number of people in the audience 35

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Fraction of children = \frac{4}{10} = \frac{2}{5} Fraction of ladies = \frac{3}{10} Fraction of men = 1 - (\frac{2}{5} + \frac{3}{10}) = \frac{3}{10} Difference between the fraction of men and children = \frac{2}{5} - \frac{3}{10} = \frac{1}{10} Now, it is given that this \frac{1}{10} is equal to 28 So, Total number of people in the audience was 28 \times 10 = 280

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Solve this Solve this 45 kgs d. 25 kgs 79. At a seminar — of the audience were children, — were ladies. The rest were men. If the 10 10 number of children was 28 more than men, then the total number of people in the audience 35

Solve this

Solve this 45 kgs d. 25 kgs 79. At a seminar — of the audience were children, — were ladies. The rest were men. If the 10 10 number of children was 28 more than men, then the total number of people in the audience 35