solve x2 - ( 3 root 2 - 2i )x - 6 root 2 i = 0 Share with your friends Share 5 Lovina Kansal answered this Dear student We have,x2-32-2ix-62i=0On comparing the given equation with the general equation ax2+bx+c=0, we geta=1, b=-32-2i and c=-62iSubstituting the values of a,b,c inα=-b+b2-4ac2a and β=-b-b2-4ac2aα=32-2i+32-2i2+242i2 and β=32-2i-32-2i2+242i2α=32-2i+32+2i22 and β=32-2i-32+2i22α=32-2i+32+2i2 and β=32-2i-32-2i2α=32 and β=-2iHence, the roots of the given equation are 32 and -2i. Regards 0 View Full Answer
