Solveeeeee itttt pleeeee Share with your friends Share 0 Suraj Basappa Belure answered this Dear student, Coefficients of the 2nd, 3rd and 4th terms in the given expansion are: C1n, C2n and C3nWe have:2×C2n=C1n+C3nDividing both sides by C2n, we get:2=C1nC2n+C3nC2n⇒2=2n-1+n-23⇒6n-6=6+n2+2-3n⇒n2-9n+14=0⇒ n=7 ∵ n≠2 as 2>3 in the 4th term Regards 0 View Full Answer