Solveeeeee itttt pleeeee

Dear student,
Coefficients of the 2nd, 3rd  and 4th terms in the given expansion are:
C1n, C2n and C3nWe have:2×C2n=C1n+C3nDividing both sides by C2n, we get:2=C1nC2n+C3nC2n2=2n-1+n-236n-6=6+n2+2-3nn2-9n+14=0 n=7  n2 as 2>3 in the 4th term
Regards

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