S o l v e t h i s : 196 T h e d i f f e r e n t i a l e q u a t i o n y d y / d x + x = a ( a i s a n y c o n s tan t ) r e p r e s e n t s ( a ) a s e t o f c i r c l e s h a v i n g c e n t r e o n t h e y - a x i s ( b ) a s e t o f c i r c l e s c e n t r e o n t h e x - a x i s ( c ) a s e t o f e l l i p s e ( d ) n o n e o f t h e s e Share with your friends Share 0 Sandeep Saurav answered this Dear Student, Given equation is ydydx+x=a.⇒ ydydx=a-x⇒y dy=(a-x) dxIntegrating both sides⇒∫y dy=∫(a-x) dx⇒y22=ax-x22+C⇒y22+x22-ax=C⇒x2+y2-2ax-2C=0comapring to the general equation of circlei.e. x2+y2+2gx+2fy+C=0whose centre is (-g, -f) and radius=g2+f2-CSo, g=a and f=0so, centre of x2+y2-2ax-2C=0and Radius =(a, 0)So, This Differential Equation representing a set of circles centred on x-axis. Regards 0 View Full Answer