Sum of Interior angles of a polygon with ( x- 2 ) sides is_____________________
Dear Student,
Sum of interior angles of a polygon with n sides is 180(n-2).
It is given that the polygon has (x-2) sides.
Therefore, sum of the interior angle of the polygon = 180(x-2-2)=180(x-4)
Regards.
Sum of interior angles of a polygon with n sides is 180(n-2).
It is given that the polygon has (x-2) sides.
Therefore, sum of the interior angle of the polygon = 180(x-2-2)=180(x-4)
Regards.