Take a 2-digit number xy and reverse its digits. Add them so that their sum becomes a 3-digit number zxz.
- Is zxz a multiple of 11?
- Is zxz less than 198?
Dear Student,
Please find below the solution to the asked query:
Given : Take a 2 - digit number xy and reverse its digits. Add them so that their sum becomes a 3 - digit number zxz.
So ,
1 ) xy + yx = zxz
10 x _ y + 10 y + x = zxz
11 x + 11 y = zxz
11 ( x + y ) = zxz
Yes zxz is multiple of 11
2 ) We know greatest two digit number = 99 and 99 + 99 = 198
But , Here we get x = y = 9
But We take x and y as different digits , So
Yes zxz is less than 198 .
Hope this information will clear your doubts about Playing with Numbers.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards
Please find below the solution to the asked query:
Given : Take a 2 - digit number xy and reverse its digits. Add them so that their sum becomes a 3 - digit number zxz.
So ,
1 ) xy + yx = zxz
10 x _ y + 10 y + x = zxz
11 x + 11 y = zxz
11 ( x + y ) = zxz
Yes zxz is multiple of 11
2 ) We know greatest two digit number = 99 and 99 + 99 = 198
But , Here we get x = y = 9
But We take x and y as different digits , So
Yes zxz is less than 198 .
Hope this information will clear your doubts about Playing with Numbers.
If you have any more doubts just ask here on the forum and our experts will try to help you out as soon as possible.
Regards