tan-1[√x(x+y+z)/√yz] + tan-1[√y(x+y+z)/√xz] + tan-1[√z(x+y+z)/√xy]=0
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tan-1[√x(x+y+z)/√yz] + tan-1[√y(x+y+z)/√xz]
+ tan-1[√z(x+y+z)/√xy]=0
prove

Brijendra Pal · Accepted Answer

Dear Student, tan-1xx+y+zyz+tan-1yx+y+zxz+tan-1zx+y+zxy= tan-1xx+y+zyz+yx+y+zxz1-xx+y+zyz×yx+y+zxz+tan-1zx+y+zxy=  tan-1x2x+y+z+y2x+y+zxyzz-x-y-zz+tan-1zx+y+zxy= tan-1-zx2x+y+z+y2x+y+zxyzx+y+tan-1zx+y+zxy=tan-1zx+y+zxy-tan-1zx+y+zx+yxyzx+y=tan-1zx+y+zxy-tan-1zx+y+zxy = 0 Proved
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tan-1[√x(x+y+z)/√yz] + tan-1[√y(x+y+z)/√xz] + tan-1[√z(x+y+z)/√xy]=0 prove

tan-1[√x(x+y+z)/√yz] + tan-1[√y(x+y+z)/√xz] + tan-1[√z(x+y+z)/√xy]=0
prove