tan A + sin A=m and tan A -sin A=n,then m^2 - n^2 = ?

Dear Student,

Please find below the solution to the asked query:

We have,     m = tan A + sin A m2 = tan A + sin A2 m2 = tan2A + sin2A + 2 tan A sin A     n = tan A - sin A n2 = tan A - sin A2 n2 = tan2A + sin2A - 2 tan A sin ANow, m2 - n2 = 4 tan A sin A =4 tan2A . sin2A=4sin2A . sin2Acos2A=4sin2A1 - cos2Acos2A=4sin2A - sin2A . cos2Acos2A=4tan2A - sin2A=4tan A + sin Atan A - sin A=4mn

Hope this would clear your doubt.

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Regards

  • 1
4mn?
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m^2 - n^2 = (m+n)(m-n) ... (1)
Now, m= (tan A + sin A )
n = (tan A- sin A)
putting the value of m and n in eq(1),
m^2 - n^2 = (m+n)(m-n)=[( tan A + sin A) + (tan A - sin A )][ (tan A + sin A) - (tan A - sin A )]
= (2 tan A )×(2 sin A)
=4 tanA.sinA
= 4 (sinA/cosA)×sin A
=4sin^2(A)/cos A
=4 (1-cos^2 (A))/cosA
= 4 (secA - cos A)
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laksha leap ur answer is not in options given.The options are 4 mn, 2 root mn, 4 root mn,2 root (m/n)
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shriram hw u got the answer can u explain
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