the angle of elevation ''a'' of a vertical tower from a point on the ground is such that its tan is 5/12. on walking 192 metres towards the tower in the same straight line , the tangent of the angle of elevation "b" is found to be 3/4 . find the height of the tower

Dear Student!

Let the height of the tower be *h* m and BC = *x *m

Suppose A and B be the position of the points on the ground subtending angles of elevation of the tower such that and respectively.

Given, AB = 192 m

In Δ BCD,

In Δ ACD,

Thus, the height of the tower is 180 m.

Cheers!

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