the argument of 1- i root 3 / 1 + 1 root 3 is

1. /3
2. 2 /3
3. 4 /3
4. -2 /3
5. /6

plz wid stEps i need it 2day itself.....

1-i root 3/ 1+i root 3

= (1-i root3)²/ (1+ i root3) (1- i root3)

=-2-2i root 3/4

=-2 (1+i root 3)/4

=-1-i root3/2

argument of z= y/x

= -root3/2 x 2/-1= root 3 (ans.) :) ..........