the argument of 1- i root 3 / 1 + 1 root 3 is

  1. /3
  2. 2 /3
  3. 4 /3
  4. -2 /3
  5. /6

plz wid stEps i need it 2day itself.....

1-i root 3/ 1+i root 3

= (1-i root3)2/ (1+ i root3) (1- i root3)

=-2-2i root 3/4

=-2 (1+i root 3)/4

=-1-i root3/2

argument of z= y/x

= -root3/2 x 2/-1= root 3 (ans.) :) ..........

  • 1
hmm..
  • 4
7pie bye 4
  • -4
Answer is 240
  • 3
Arg = tan-b/a

  • 2
What are you looking for?