The axis of the parabola x2 - 4x - y + 1 = 0 is ? Thank you

x²-4x-y+1=0  (Given eq of parabola)
We need to rearrange this eq. .
x²-4x+4-3=y
(x-2)² =(y+3)
(x-2)² =4*(1/4) (y+3)   .....(1)
This eq can be compared with standard eq of parabola : X² = 4aY
where X=x-2
           a=1/4
           Y=y+3
For standard parabola axis is at : (0,a)
Therefore for given parabola, according to eq 1 :-
Coordinates of the axis are : x-2=0
                                              x=2 
Also, y+3=1/4
         y=-11/4 
So axis is at : (2,-11/4)


HOPE THIS HELPS!!! ;)