The base of an isosceles triangle is 4/3 cm. The perimeter of triangle is 4 2/15cm. what is the length of either of the remaining equal sides?
PERIMETER OF THE TRIANGLE= SUM OF THREE SIDES OF A TRIANGLE
ONE SIDE = 4/3CM (GIVEN)
PERIMETER = 42/15CM(GIVEN)
HENCE PERIMETER - ONE SIDE OF THE TRIANGLE =LENGTH OF THE TWO SIDES OF THE TRIANGLE.
OR, 42/15 - 4/3 = 22/15
THEREFORE, LENGTH OF EACH OF THE REMAINING TWO SIDES = (22/15)/2 = 11/15
ANSWER = 11/15
let the equal sides be x
perimeter=4 2/15=62/15 cm
acoording to the question,
(lcm of 15 and 3=15 :. the fraction without the denominator as 15 will be changed)
x=42/15*reciprocal of 2