the cartesian equations of sides BC,CA and AB of a triangel are repectively ur =arx+bry+cr=0 ,r=1,2,3. show that the equation of the straight line passing through A and bisecting side BC is

u3 / a3b1-a1b3 = u2/a1b2-a2b1.

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I don't know
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Solve any one

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Find eq of line passing A is u2+ku3=0,it is passing through mid point of BC and find k weget result
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Please send answer
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