The cost of 2 kg of apples and 1 kg of grapes on a day was found to be Rs 160. After a month, the cost of 4 kg of apples and 2 kg of grapes is Rs 300. Represent the situation algebraically and geometrically.
Let the cost of 1 kg of apples be Rs x.
And, cost of 1 kg of grapes = Rs y
According to the question, the algebraic representation is
For
,
The solution table is
|
x |
50 |
60 |
70 |
|
y |
60 |
40 |
20 |
For 4x + 2y = 300,
The solution table is
|
x |
70 |
80 |
75 |
|
y |
10 |
−10 |
0 |
The graphical representation is as follows.
