1. the de broglie wavelength of a neutron at 27 degree celcius is lambda. what will be its wavelength at 927 degree celcius?

Wavelength is inversely proportional to square root of Tand next convert degree Celsius into K by adding with 273 then apply in the formula you will get the answer wavelength divided by 2
  • 11
  • -5
What are you looking for?