the diameter of front and rear wheel of a tractor are 0.63m and 1.54m respectively. the rear wheel is rotating at 270/11 revolutions per minute. find 1. the no. of revolutions per minute of the front wheel
2. the distance travelled by the tractor in 1/2 hours.

Dear Student,

diameter of front wheel = 63 cm = 0.63 mradius of front wheel = 0.632 mdiameter of rear wheel = 1.54 mradius of rear wheel = 1.542 = 0.77 mCircumference of rear wheel = 2πr=2×227×0.77= 4.84 mDistance covered by rear wheel in 27011 revolutions = 27011×4.84 = 118.8 mCircumference of front wheel = 2πr= 2×227×0.632= 1.98 mBut, distance covered by front wheel is equal to distance covered by rear wheel = 118.8 mi Number of revolutions made by front wheel in one minute = 118.81.98 = 60 revolutions.ii distance travelled in 40 minutes = 118.8×40 = 4,752 m

Regards

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