The digits of a two digit number differ by 3.If the digits are interchanged and the resulting number is added to the original number , we get 143 .what can be the orginal number? Share with your friends Share 0 Varun Rawat answered this Dear Student,Let the digit at units place = xThen digit at tens place = x + 3Now, original number = 10x+3+x = 10x + 30 + x = 11x + 30Now, when the digits are reversed, then new number = 10x + x + 3 = 11x + 3Now, according to question :11x + 30 + 11x + 3 = 143⇒22x = 143 - 33⇒22x = 110⇒x = 5So, original number = 11×5 + 30 = 55 + 30 = 85OrLet the digit at units place = xThen digit at tens place = x - 3Now, original number = 10x-3+x = 10x - 30 + x = 11x - 30Now, when the digits are reversed, then new number = 10x + x - 3 = 11x - 3Now, according to question :11x - 30 + 11x - 3 = 143⇒22x = 143 + 33⇒22x = 176⇒x = 8So, original number = 11×8 - 30 = 88-30 = 58Regards 1 View Full Answer