The emf of the battery shown in figure, is (a) 12 V (b) 13 V (c) 16 V (d) 18 V Share with your friends Share 34 Sanjay Singh answered this Dear student equivalent resistance of the last two 1Ω resistor =2Ω Distribution of current is as shown in figure for figure 1 equivalent resistance is (2Ω and 1Ω are connected in series and 4Ω in parallel with them)1R1=13+14R1=3×47=127in figure 2Ω and 127Ω are connected in series R2=2+127=267Current supplied by cell I=ER2=7E26but 127Ω resistor consist of 3 and 4Ω resistors in parallel so Current in 3Ω resistor is i=(43+4)×I=47×7E26=2E13but 2E13=2E=13voltRegards -15 View Full Answer