The EMF of the cell is balance against a length of 217cm of a potentiometer wire. When the cell is shunted by a resistance of 15ohm, the balancing length is 200cm. Find the internal resistance of the cell.

Dear student,r=l1-l2l2 Rl1=217 cm = 2.17 ml2=200 cm = 2 mR=15 ohmr=2.17-2.002×2r=0.17 ohmRegards

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