The equations of the tangents drawn from the origin to the circle x^{2} + y^{2} - 2rx- 2hy + h^{2}=0 are :

- x=0, y=0
- (h
^{2}-r^{2})x-2rhy=0, x=0 - y=0,x=4
- (h
^{2}-r^{2})x + 2rhy=0,x=0.

Dear Student!

Here is the answer to your query.

The equation of pair of tangent to the circle *x*^{2} + *y*^{2} + 2*gx* + 2*fy* + *c* = 0 from point (*x*_{1}, *y*_{1}) is

Thus, the equation of pair of tangent to the circle *x*^{2} + *y*^{2} – 2*rx* – 2*hy* + *h*^{2} = 0 from origin (0, 0) is

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